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Distribution Math Questions and Charts
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Distribution
Math Problems & Charts
You are adding 6 lbs/day of chlorine gas to a flow of 277 gpm and your total
chlorine residual is 1.5 mg/L. What is your chlorine demand in mg/L?
Flow, MGD = 277 gpm ÷ 694
gpm/mgd = 0.4 MGD
Chlorine Dose, mg/L = 6
lbs/day ÷ 8.34 lbs/gal ÷ 0.4 MGD = 1.8 mg/L
Chlorine demand, mg/L = 1.8
mg/L = 1.5 mg/L = 0.3 mg/L
Click on the
thumbnail below for the answers for the chart of pump station math
for cylindrical tanks.
Click on the
thumbnail below for the answers for the chart of pump station math
for rectangular tanks.
Click on the
thumbnail below for the answers for the chart of pipe math.
Match |
1 |
The units for pressure are |
A |
Divided by |
2 |
Head is expressed in |
B |
2.31 |
3 |
Velocity is measured in |
C |
0.434 psi |
4 |
Units of flow |
D |
psi |
5 |
Pressure times _______ = Head |
E |
fps |
6 |
Head __________ 2.31 = Pressure |
F |
1440 |
7 |
20 psi = |
G |
694 gpm |
8 |
1 MGD = |
H |
cfs |
9 |
A head loss of 7 feet = |
I |
3 psi |
|
|
J |
Times |
|
|
K |
ft |
|
|
L |
46.2 ft |
|
|
M |
Subtracted by |
1 = D
2 = K
3 = E
4= H
5 = B
6 = A
7 = L
8 = G
9 = I
The formula for the volume of
a rectangular tank is
A. (Length)(Width)
B.
(0.785)(Diameter2)
C. (Length)(Width)(Height)
D.
(0.785)(Diameter2)(Height)
The correct answer is C. (Length)(Width)(Height)
A is the formula for the area of
a rectangle
B is the formula for the area of
a circle
D
is the formula for the volume of a cylinder
The formula for the volume of
a cylindrical tank is
A. (Length)(Width)
B.
(0.785)(Diameter2)
C. (Length)(Width)(Height)
D.
(0.785)(Diameter2)(Height)
The correct answer is D.
(0.785)(Diameter2)(Height)
A is the formula for the area of
a rectangle
B is the formula for the area of
a circle
C is the formula for the volume
of a rectangle
Given a tank measures 50
feet long, 25 feet wide, and 15 ft deep, calculate:
- Surface area in ft2
- Cross-sectional area in
square feet
- Volume in cf
- Capacity in gallons
The correct answers are:
Surface area in ft2
= Length, ft x Width, ft = 50 ft x 25 ft = 1250 ft2
-
Cross-sectional area in square feet
Cross-sectional area is ft2 =
Width, ft x Depth, ft = 25 ft x 15 ft = 375 square feet
Volume in cf = Length, ft x Width, ft x
Depth, ft = 50 ft x 25 ft x 15 ft = 18,750 cf
Capacity in gallons = Vol in cf x 7.5
gal/cf = 18,750 cf x 7.5 gal/cf = 140,625 gal
For questions or comments,
call 515-313-1159
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